At Mill Lane Primary, the corridors buzzed with whispers louder than the fire alarm. The famous (and slightly ridiculous) school painting – The Majestic Turnip – had vanished overnight. It was supposed to hang proudly in the hall for the upcoming art competition, but now only a lonely hook and a faint square of dust remained. For some, it was a tragedy, for others, losing a painting of a giant vegetable was no great loss.
The five detectives, already infamous for solving mysteries the adults couldn’t, were called in. Trouble never found them quietly. This time, it arrived with glitter footprints, biscuit crumbs, and a very nervous headteacher.
The Suspects
Mr Tippet , the art teacher, was pale and trembling. He had fainted earlier that morning when a Year 3 boy spilt blue paint on the new carpet. “But this is far worse! ” he wailed dramatically, clutching his forehead like a Shakespearean actor.
Mrs Crumb , the school caretaker, stood proudly with her mop. “No need for detectives, a roll of duct tape fixes everything,” she declared, even though duct tape clearly couldn’t replace a painting.
Headteacher Mr Pike muttered nervously about curses. “Mark my words,” he said. “That turnip brings bad luck. First the pigeon incident, then the leaking roof… and now this!”
The detectives exchanged glances. It was going to be one of those days!
Clues Begin to Surface
On the floor, Jack’s sharp eyes landed on a half-eaten custard cream, lying like a guilty golden breadcrumb suspiciously close to the bare patch of wall where the painting once hung in pride. Its creamy insides oozed ever so slightly, as though the biscuit itself were sweating under the pressure of being caught at the scene.
Nearby, a glitter trail shimmered like a disco carpet leading straight to the Year 6 classroom. It clung to shoes, stuck in corners, and refused to be brushed away, as though determined to make its presence known. The whole scene had all the subtlety of an army of fairies sneezing glitter bombs until even the floor finally gave up.
Amira began pacing, muttering, piecing together a crime scene under her breath:
“The painting was last seen at 3:15 pm. By 3:20, the hall was empty. Mr Tippet signed out at 15:05, Mrs Crumb left at half past three, and a student nipped back at twenty to four for a forgotten lunchbox. By 3:45 – poof – the painting was gone.”
❌ Mr Tippet left before 3:30, so he wasn’t around when the painting disappeared.
Ask Oliver (150 Credits)
Oliver: “Let us draw a timeline to track everyone’s movements.”
Step 1: Draw a horizontal line on your paper and mark the start time at 3:15 pm and the end time at 3:45 pm.
Step 2: Convert all the given times into the same format. For example, what is 15:05 on a 12-hour clock?
Step 3: Plot everyone’s departure time on your line. Look closely to see who was actually left in the building when the painting vanished.
Ask Emma (150 Credits)
Emma: “We need to list everyone who entered or left during the 3:15–3:45 pm window!”
Step 1: Check Mr Tippet: He signed out at 15:05 (3:05 pm) — that is before 3:15 pm, so rule him out!
Step 2: Check Mrs Crumb: She left at half past three (3:30 pm) — right in the middle of our window!
Step 3: Check the student: Returned at twenty to four (3:40 pm) — also inside our window!
❌ Mrs Crumb was there, but not alone – the student came back at 3:40.
Ask Oliver (150 Credits)
Oliver: “Let us draw a timeline to track everyone’s movements.”
Step 1: Draw a horizontal line on your paper and mark the start time at 3:15 pm and the end time at 3:45 pm.
Step 2: Convert all the given times into the same format. For example, what is 15:05 on a 12-hour clock?
Step 3: Plot everyone’s departure time on your line. Look closely to see who was actually left in the building when the painting vanished.
Ask Emma (150 Credits)
Emma: “We need to list everyone who entered or left during the 3:15–3:45 pm window!”
Step 1: Check Mr Tippet: He signed out at 15:05 (3:05 pm) — that is before 3:15 pm, so rule him out!
Step 2: Check Mrs Crumb: She left at half past three (3:30 pm) — right in the middle of our window!
Step 3: Check the student: Returned at twenty to four (3:40 pm) — also inside our window!
❌ Mr Tippet had already gone by then, so all three weren’t together.
Ask Oliver (150 Credits)
Oliver: “Let us draw a timeline to track everyone’s movements.”
Step 1: Draw a horizontal line on your paper and mark the start time at 3:15 pm and the end time at 3:45 pm.
Step 2: Convert all the given times into the same format. For example, what is 15:05 on a 12-hour clock?
Step 3: Plot everyone’s departure time on your line. Look closely to see who was actually left in the building when the painting vanished.
Ask Emma (150 Credits)
Emma: “We need to list everyone who entered or left during the 3:15–3:45 pm window!”
Step 1: Check Mr Tippet: He signed out at 15:05 (3:05 pm) — that is before 3:15 pm, so rule him out!
Step 2: Check Mrs Crumb: She left at half past three (3:30 pm) — right in the middle of our window!
Step 3: Check the student: Returned at twenty to four (3:40 pm) — also inside our window!
✅ That’s right!
Biscuit Fractions
On a chair in the hall, Lucy found an open biscuit packet. Out of 20 biscuits, exactly 3/5 had been eaten.
❌ 10 is half, not 3/5 eaten.
Ask Jack (150 Credits)
Jack: “Let us find out how many biscuits make up one fifth first.”
Step 1: Divide the total number of biscuits by the denominator. What is 20 divided by 5?
Step 2: Multiply that answer by the numerator to find out exactly how many biscuits were eaten.
Step 3: Read the question carefully. Do you need the number of eaten biscuits or the number of biscuits left over?
Ask Amira (150 Credits)
Amira: “Let us use our common sense to check our thoughts.”
Half of the packet would be exactly 10 biscuits. The fraction 3/5 is slightly more than a half. This means more than 10 biscuits were eaten. Use that fact to rule out some of the answers.
❌ 12 would mean only 8 were eaten, not 12.
Ask Jack (150 Credits)
Jack: “Let us find out how many biscuits make up one fifth first.”
Step 1: Divide the total number of biscuits by the denominator. What is 20 divided by 5?
Step 2: Multiply that answer by the numerator to find out exactly how many biscuits were eaten.
Step 3: Read the question carefully. Do you need the number of eaten biscuits or the number of biscuits left over?
Ask Amira (150 Credits)
Amira: “Let us use our common sense to check our thoughts.”
Half of the packet would be exactly 10 biscuits. The fraction 3/5 is slightly more than a half. This means more than 10 biscuits were eaten. Use that fact to rule out some of the answers.
❌ 6 suggests just 14 eaten, which doesn’t match 3/5.
Ask Jack (150 Credits)
Jack: “Let us find out how many biscuits make up one fifth first.”
Step 1: Divide the total number of biscuits by the denominator. What is 20 divided by 5?
Step 2: Multiply that answer by the numerator to find out exactly how many biscuits were eaten.
Step 3: Read the question carefully. Do you need the number of eaten biscuits or the number of biscuits left over?
Ask Amira (150 Credits)
Amira: “Let us use our common sense to check our thoughts.”
Half of the packet would be exactly 10 biscuits. The fraction 3/5 is slightly more than a half. This means more than 10 biscuits were eaten. Use that fact to rule out some of the answers.
✅ Perfect, 8 biscuits left. The crumbs don’t lie, but the culprit might!
.
The Glitter Trail
The glitter trail measured 4 metres in total. The detectives noticed that for every 30 centimetres of silver glitter, there was 0.1 metre of gold glitter.
❌ 2 metres would mean a 1:1 ratio, not 3:1.
Ask Jack (150 Credits)
Jack: “We need to make sure all our measurements speak the same language.”
Step 1: Convert all the measurements to centimetres. What is 0.1 metres written in centimetres?
Step 2: Add your silver and gold amounts together to find the length of one complete glitter ratio block.
Step 3: Convert the 4-metre trail into centimetres. How many times does your small ratio block fit into the total length of the trail?
Ask Lucy (150 Credits)
Lucy: “Look for the relationship between the parts.”
For every section of glitter, there are three parts of silver and one part of gold. This means the entire trail is made of four equal parts in total. How can you simply divide the grand total of 4 metres by 4 to find the size of one part?
❌ 3 metres would mean almost all silver glitter missing, which isn’t right.
Ask Jack (150 Credits)
Jack: “We need to make sure all our measurements speak the same language.”
Step 1: Convert all the measurements to centimetres. What is 0.1 metres written in centimetres?
Step 2: Add your silver and gold amounts together to find the length of one complete glitter ratio block.
Step 3: Convert the 4-metre trail into centimetres. How many times does your small ratio block fit into the total length of the trail?
Ask Lucy (150 Credits)
Lucy: “Look for the relationship between the parts.”
For every section of glitter, there are three parts of silver and one part of gold. This means the entire trail is made of four equal parts in total. How can you simply divide the grand total of 4 metres by 4 to find the size of one part?
❌ 4 metres means only gold, no silver at all.
Ask Jack (150 Credits)
Jack: “We need to make sure all our measurements speak the same language.”
Step 1: Convert all the measurements to centimetres. What is 0.1 metres written in centimetres?
Step 2: Add your silver and gold amounts together to find the length of one complete glitter ratio block.
Step 3: Convert the 4-metre trail into centimetres. How many times does your small ratio block fit into the total length of the trail?
Ask Lucy (150 Credits)
Lucy: “Look for the relationship between the parts.”
For every section of glitter, there are three parts of silver and one part of gold. This means the entire trail is made of four equal parts in total. How can you simply divide the grand total of 4 metres by 4 to find the size of one part?
✅ You are on the right track!
The Locker Combination
The detectives suspected someone had hidden the painting in a cloakroom locker. The lock opened with a 3-digit code, and the clues scribbled on the wall read:
“This reminds me of algebra,” Emma said quietly, studying the pattern.
❌ Hmmm, that doesn’t work.
Ask Emma (150 Credits)
Emma: “Let us set up a system to crack this code.”
Step 1: Call the first digit the mystery box. The middle digit is exactly two of those boxes.
Step 2: The last digit is the mystery box plus 3.
Step 3: If you add all the boxes and the extra 3 together, you must get 15. What must the value of one single mystery box be?
Ask Amira (150 Credits)
Amira: “Trial and error is a perfectly valid mathematical strategy.”
Start by guessing the first digit. What if the first digit is 2? The middle would be 4, and the last would be 5. Do those add up to 15? Adjust your starting number upwards until the total matches perfectly.
✅ Remarkable codebreaking ability!
The Assembly Graph
The assembly chart looked like a mystery all on its own. Of 180 pupils, just 135 had arrived, leaving a crowd of invisible students lurking somewhere in the shadows. If these absentees were scattered evenly across the five classes, how many class-sized escape artists would be in each class?
❌ 7 × 5 = 35, too few.
Ask Lucy (150 Credits)
Lucy: “Let us break this into two simple mental steps.”
Step 1: First, find the difference between the total number of pupils and the number who actually arrived. What is 180 subtract 135?
Step 2: Now take that group of missing pupils. The question says they are scattered evenly across 5 classes.
Step 3: What operation do we use when we share a number evenly into groups?
Ask Oliver (150 Credits)
Oliver: “Picture the missing pupils as a block.”
Imagine a bar model showing 180 total pupils. One part is 135. Find the value of the missing part. Now draw 5 empty boxes underneath. How do you split that missing part into the 5 boxes evenly?
❌ 8 × 5 = 40, too few.
Ask Lucy (150 Credits)
Lucy: “Let us break this into two simple mental steps.”
Step 1: First, find the difference between the total number of pupils and the number who actually arrived. What is 180 subtract 135?
Step 2: Now take that group of missing pupils. The question says they are scattered evenly across 5 classes.
Step 3: What operation do we use when we share a number evenly into groups?
Ask Oliver (150 Credits)
Oliver: “Picture the missing pupils as a block.”
Imagine a bar model showing 180 total pupils. One part is 135. Find the value of the missing part. Now draw 5 empty boxes underneath. How do you split that missing part into the 5 boxes evenly?
❌ 10 × 5 = 50, too many.
Ask Lucy (150 Credits)
Lucy: “Let us break this into two simple mental steps.”
Step 1: First, find the difference between the total number of pupils and the number who actually arrived. What is 180 subtract 135?
Step 2: Now take that group of missing pupils. The question says they are scattered evenly across 5 classes.
Step 3: What operation do we use when we share a number evenly into groups?
Ask Oliver (150 Credits)
Oliver: “Picture the missing pupils as a block.”
Imagine a bar model showing 180 total pupils. One part is 135. Find the value of the missing part. Now draw 5 empty boxes underneath. How do you split that missing part into the 5 boxes evenly?
✅ Your maths skills are improving!
The Final Twist
The detectives gathered in the Year 6 cloakroom, eyes darting from the empty wall hook to the glitter-sprinkled floor. Jack leaned down and picked up a few stray custard cream crumbs.
Jack: “These match the ones near the hall. Someone dropped their snack while this chaos started.”
Lucy: “Right… so that rules out Mrs Crumb. She doesn’t eat custard creams while working.”
Emma: “And Mr Tippet? He passed out when a Year 3 spilt paint earlier. In all that chaos, he probably forgot the glitter in the hall. Besides, I’ve never once seen him touch a biscuit without looking horrified!”
Oliver: “And the headteacher? He’s been hiding behind his desk, muttering about cursed turnips. No glitter, no biscuits, and definitely no sneaky lockers.”
The detectives exchanged knowing glances.
Lucy: “So all the adults are out . That leaves… someone who had both opportunity and motive.”
Jack pointed to the glitter trail: “It leads straight to a locker . Someone carried the painting through the corridor, and that is how this trail magically appeared.”
Emma: “And inside the locker, look! Custard cream crumbs, a piece of wrapper, and a scribbled three-digit code. Someone returned for a lunchbox and couldn’t resist a prank.”
Oliver: “The attendance chart fits too. Danny and a few others skipped assembly. They had time to admire the painting while everyone else was stuck in the hall.”
Lucy: “So the glitter, the biscuits, the locker, the code, and the absentees… it all points to one person.”
Now, the most important question is …
❌ Mr Tippet (art teacher): He couldn’t have stolen the painting, as he faints if anyone so much as sneezes near a carpet, let alone pulls off a heist.
❌ Mrs Crumb (caretaker): She wasn’t guilty. Her biggest crime that day was waging war against a particularly stubborn mop bucket.
❌ Mr Pike (headteacher): He wasn’t the thief. He was too busy muttering about “cursed paintings” and hiding behind his office blinds.
They turned to face the culprit – Danny, who was nervously trying to hide a faint grin.
Jack: “Danny, it’s you! You saw the turnip, decided a prank would be hilarious, and didn’t realise you were dragging a glitter comet across the school.”
Danny: “Okay, okay, I admit it! I thought it would be funny… I didn’t mean for the whole school to panic.”
The detectives laughed in relief. “Only Danny,” sighed Lucy. “Who else would steal a turnip painting, drop half a biscuit packet in the hall, and leave a glitter trail across the whole school just to make everyone gasp?”
The painting was returned, the mystery solved, and the detectives had enjoyed every absurd, sparkly, custard-stained step of the chase. And we hope you enjoyed it too. 🙂
Case Closed